Congruent Triangles and Geometric Proof
Two shapes are congruent if they are exactly the same shape and size. Edexcel tests this in two ways: naming the right condition (SSS, SAS, ASA, RHS) and writing a short congruence proof. The proof is a 3–4 mark question that rewards a clear, reasoned layout.
1What congruent means
Congruent shapes are identical in shape and size. One can be moved onto the other by a rotation, reflection or translation. Similar shapes have the same shape but can be a different size.
Similar: corresponding angles are equal and sides are in the same ratio.
2The four conditions
To prove two triangles are congruent, you only need to show one of these:
- AAA doesn’t prove congruence. Three equal angles only shows the triangles are similar.
- SSA (two sides and an angle that is not between them) doesn’t prove congruence, except for the right-angled case RHS.
3How to write a congruence proof
- Name the two triangles, with corresponding vertices in the same order.
- State three facts, each with a reason (given, common side, vertically opposite angles, property of a square, …).
- Name the condition (SSS, SAS, ASA or RHS) and conclude that the triangles are congruent.
- AB = CD (opposite sides of a parallelogram are equal).
- BC = DA (opposite sides of a parallelogram are equal).
- AC = CA (common side).
- So triangle ABC ≅ triangle CDA (SSS).
4Using congruence to prove other results
Once two triangles are congruent, all their corresponding parts are equal. That lets you prove facts about angles and lengths.
- AB = AC (given).
- BM = CM (M is the midpoint of BC).
- AM = AM (common side).
- So triangles ABM and ACM are congruent (SSS).
- Therefore angle ABM = angle ACM, that is, angle ABC = angle ACB (corresponding angles of congruent triangles).
- AM = BM (M is the midpoint of AB).
- CM = DM (M is the midpoint of CD).
- Angle AMC = angle BMD (vertically opposite angles).
- So triangle AMC ≅ triangle BMD (SAS).
- Using AAA or SSA as a congruence condition.
- Using SAS when the angle is not between the two sides.
- Stating facts without reasons.
- Writing the vertices in a mismatched order, e.g. ABC ≅ DFE when A ↔ D, B ↔ E.
- Confusing congruent (same size) with similar (scaled).
★Key Vocabulary Recap
- Congruent (≅)
- Identical in shape and size.
- Included angle
- The angle between two given sides.
- Hypotenuse
- The longest side of a right-angled triangle, opposite the right angle.
- Common side
- A side shared by both triangles.
- G5: use the basic congruence criteria for triangles (SSS, SAS, ASA, RHS).
- G6: apply angle facts, triangle congruence, similarity and properties of quadrilaterals to conjecture and derive results; construct simple proofs.
- G7: identify congruent and similar shapes.
Practice questions
Congruent Triangles and Geometric Proof — Practice Questions
10 exam-style questions (24 marks), building from warm-up to grade 8–9. Show full working: Edexcel gives method marks even when the final answer is wrong.
- (1 mark)Grade 4Two triangles have sides 5 cm, 7 cm, 9 cm and 9 cm, 5 cm, 7 cm. Are they congruent? Give the condition.
- (1 mark)Grade 4Two triangles each have angles 40°, 60° and 80°. Explain why this is not enough to show they are congruent.
- (1 mark)Grade 5Triangle P has sides 6 cm and 8 cm with an angle of 50° between them. Triangle Q has sides 6 cm and 8 cm with an angle of 50° between them. Which condition shows they are congruent?
- (1 mark)Grade 5Two right-angled triangles both have a hypotenuse of 13 cm and one other side of 5 cm. Are they congruent? Give the condition.
- (2 marks)Grade 5Triangle ABC ≅ triangle DEF, with A ↔ D, B ↔ E and C ↔ F. Angle ABC = 72°, AB = 9 cm and EF = 11 cm. Write down angle DEF, the length DE and the length BC.
- (3 marks)Grade 6ABCD is a parallelogram. Prove that triangle ABC is congruent to triangle CDA.
- (3 marks)Grade 6Lines AB and CD intersect at M, the midpoint of both. Prove that triangles AMC and BMD are congruent.
- (4 marks)Grade 7ABCD is a kite with AB = AD and CB = CD. Prove that angle ABC = angle ADC.
- (4 marks)Grade 7ABCD is a square. E lies on BC and F lies on CD, with BE = CF. Prove that triangles ABE and BCF are congruent.
- (4 marks)Grade 8Triangle ABC is isosceles with AB = AC. D is the point on BC such that AD is perpendicular to BC. Prove that D is the midpoint of BC.
Hint
Which condition uses a right angle and a hypotenuse?
Worked solutions
Show worked solutions
Congruent Triangles and Geometric Proof — Worked Solutions
Full worked solutions to all 10 questions (24 marks), set out the way an Edexcel examiner wants to see them.
- (1 mark)Grade 4Two triangles have sides 5 cm, 7 cm, 9 cm and 9 cm, 5 cm, 7 cm. Are they congruent? Give the condition.Solution
- All three pairs of sides are equal.
Yes, SSS - (1 mark)Grade 4Two triangles each have angles 40°, 60° and 80°. Explain why this is not enough to show they are congruent.Solution
- Equal angles only show they are the same shape (similar). One could be an enlargement of the other.
AAA shows similarity, not congruence - (1 mark)Grade 5Triangle P has sides 6 cm and 8 cm with an angle of 50° between them. Triangle Q has sides 6 cm and 8 cm with an angle of 50° between them. Which condition shows they are congruent?Solution
- Two sides and the included angle.
SAS - (1 mark)Grade 5Two right-angled triangles both have a hypotenuse of 13 cm and one other side of 5 cm. Are they congruent? Give the condition.Solution
- Right angle, hypotenuse and one side are equal.
Yes, RHS - (2 marks)Grade 5Triangle ABC ≅ triangle DEF, with A ↔ D, B ↔ E and C ↔ F. Angle ABC = 72°, AB = 9 cm and EF = 11 cm. Write down angle DEF, the length DE and the length BC.Solution
- Corresponding parts of congruent triangles are equal.
- DEF = ABC = 72°; DE = AB = 9 cm; BC = EF = 11 cm.
72°, 9 cm, 11 cm
- (3 marks)Grade 6ABCD is a parallelogram. Prove that triangle ABC is congruent to triangle CDA.Solution
- AB = CD and BC = DA (opposite sides of a parallelogram are equal).
- AC is common.
- So ABC ≅ CDA (SSS).
SSS - (3 marks)Grade 6Lines AB and CD intersect at M, the midpoint of both. Prove that triangles AMC and BMD are congruent.Solution
- AM = BM and CM = DM (M is the midpoint of both lines).
- Angle AMC = angle BMD (vertically opposite).
- So AMC ≅ BMD (SAS).
SAS - (4 marks)Grade 7ABCD is a kite with AB = AD and CB = CD. Prove that angle ABC = angle ADC.Solution
- In triangles ABC and ADC: AB = AD (given), CB = CD (given), AC is common.
- So triangle ABC ≅ triangle ADC (SSS).
- Therefore angle ABC = angle ADC (corresponding angles of congruent triangles).
Proved via SSS - (4 marks)Grade 7ABCD is a square. E lies on BC and F lies on CD, with BE = CF. Prove that triangles ABE and BCF are congruent.Solution
- AB = BC (sides of a square are equal).
- Angle ABE = angle BCF = 90° (angles of a square).
- BE = CF (given).
- So triangle ABE ≅ triangle BCF (SAS).
SAS - (4 marks)Grade 8Triangle ABC is isosceles with AB = AC. D is the point on BC such that AD is perpendicular to BC. Prove that D is the midpoint of BC.Solution
- In triangles ABD and ACD: angle ADB = angle ADC = 90° (AD ⟂ BC).
- AB = AC (given): these are the hypotenuses.
- AD is common.
- So ABD ≅ ACD (RHS), hence BD = CD and D is the midpoint of BC.
Proved via RHS
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