Advanced Factorising & Completing the Square — Solutions
Full worked solutions, with method and final answer for every part.
Question 1
(a)This is a difference of two squares: a² − b² = (a−b)(a+b), with a=x, b=7.
(x − 7)(x + 7)
Question 2
(a)Find two numbers that multiply to 12 and add to 7: 3 and 4.
(x + 3)(x + 4)
Question 3
(a)Half of 6 is 3, so start with (x+3)². Expanding (x+3)² gives x²+6x+9, which is 4 more than the original expression, so subtract 4.
(x + 3)² − 4, minimum value = −4 (when x = −3)
Question 4
(a)Difference of two squares: a²−b² = (a−b)(a+b).
(x − 4)(x + 4)
Question 5
(a)Find factors of (2×3=6) that add to 7: 1 and 6. Split the middle term and factorise by grouping.
(2x + 1)(x + 3)
Question 6
(a)Half of −4 is −2, so start with (x−2)². Expanding gives x²−4x+4, which is 5 more than the original, so subtract 5.
(x − 2)² − 5
Question 7
(a)Take out the common factor 3, then apply difference of squares to what remains.
3(x² − 4) = 3(x−2)(x+2)
Question 8
(a)Find two numbers multiplying to 20 and adding to −9: −4 and −5.
(x − 4)(x − 5)
Question 9
(a)From (x−2)² − 5 = 0, (x−2)² = 5, so x − 2 = ±√5.
x = 2 ± √5, i.e. x ≈ 4.24 or x ≈ −0.24
Question 10
(a)Take out the common factor 5, then apply difference of two squares.
5(x−2)(x+2)
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