IGCSE Maths 0580 Money and Exchange Rates Past Paper Questions and Worked Solutions

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IGCSE Maths (0580) · Number · 1.16

Every money and exchange rates question from 12 Cambridge IGCSE Mathematics (0580) past papers (May/June 2025 to May/June 2026), syllabus section 1.16. 15 questions covering Core and Extended tiers, ordered from Core to Extended. Each question is labelled with its question paper code (for example 0580/31/M/J/26) and every final answer matches the official Cambridge mark scheme. Try each question first, then click “Show solution” to check your working. This page is part of our IGCSE Maths 0580 Number past paper questions.

0580 Money and Exchange Rates past paper questions: Core (Papers 1 and 3)

13 marksCore

May/June 2026 · Paper 3 · 0580/31/M/J/26 · Q1

The table shows a shopping bill for three items. Complete the table.

itemcost per kgnumber of kgtotal
potatoes$2.183.5$7.63
oranges$1.486$
onions$5.2$
total cost$29.25
Show solution
  1. Total = cost per kg × number of kg.
  2. Oranges: 1.48 × 6 = $8.88
  3. The three totals add up to $29.25, so onions total = 29.25 − 7.63 − 8.88 = $12.74
  4. Onions cost per kg = total ÷ number of kg = 12.74 ÷ 5.2 = $2.45
  5. Check: 2.45 × 5.2 = 12.74 ✓
Answer $8.88 $12.74 $2.45
21 markCore

May/June 2026 · Paper 3 · 0580/31/M/J/26 · Q3

Arya changes 250 pounds into dollars. The exchange rate is 1 pound = $1.26. Calculate the amount that Arya receives.

Show solution
  1. Each pound is worth $1.26, so multiply the number of pounds by 1.26.
  2. 250 × 1.26 = $315
Answer $315
33 marksCore

May/June 2026 · Paper 3 · 0580/32/M/J/26 · Q3

A vase costs $5.45. Tim has $35. Work out the maximum number of vases Tim can buy and the change he receives.

Show solution
  1. Divide the money by the price: 35 ÷ 5.45 = 6.42…
  2. Tim cannot buy part of a vase, so round down: 6 vases
  3. Cost of 6 vases = 6 × 5.45 = $32.70.
  4. Change = 35.00 − 32.70 = $2.30
Answer 6 vases $2.30
41 markCore

May/June 2026 · Paper 3 · 0580/32/M/J/26 · Q9

Pip changes 500 euros into dollars when the exchange rate is $1 = 0.95 euros. Calculate the amount Pip receives.

Show solution
  1. The exchange rate says each dollar costs 0.95 euros.
  2. So the number of dollars = euros ÷ 0.95 = 500 ÷ 0.95 = 526.315…
  3. Round money to 2 decimal places: $526.32
  4. Check: 526.32 × 0.95 ≈ 500 euros ✓
Answer $526.32
53 marksCore

May/June 2026 · Paper 3 · 0580/33/M/J/26 · Q18

A camera costs $735 in Sydney and 435 euros in Rome. The exchange rate is $1 = 0.58 euros. Calculate the difference in the cost. Give your answer in dollars.

Show solution
  1. Change the Rome price into dollars. Each dollar is 0.58 euros, so divide by 0.58.
  2. 435 ÷ 0.58 = $750.
  3. Difference = 750 − 735 = $15
Answer $15
63 marksCore

Feb/Mar 2026 · Paper 3 · 0580/32/F/M/26 · Q4

A café charges $5.75 for a cake and $4.40 for a milkshake. Sue buys 3 cakes and 2 milkshakes. Work out how much change she receives from a $50 note.

Show solution
  1. Cost of 3 cakes = 3 × $5.75 = $17.25.
  2. Cost of 2 milkshakes = 2 × $4.40 = $8.80.
  3. Total = 17.25 + 8.80 = $26.05.
  4. Change = 50.00 − 26.05 = $23.95
Answer $23.95
72 marksCore

Feb/Mar 2026 · Paper 3 · 0580/32/F/M/26 · Q15

The price of a train ticket is either $85 or 75 euros. The exchange rate is 1 euro = $1.18. Calculate the difference between the two prices. Give your answer in euros.

Show solution
  1. Change $85 into euros so both prices use the same currency.
  2. 1 euro = $1.18, so $85 = 85 ÷ 1.18 = 72.03 euros.
  3. Difference = 75 − 72.03 = 2.97 euros
Answer 2.97 euros
82 marksCore

Oct/Nov 2025 · Paper 1 · 0580/12/O/N/25 · Q2

Tom buys 2 books costing $8.20 each. Work out how much change he receives from $20.

Show solution
  1. Cost of 2 books = 2 × $8.20 = $16.40.
  2. Change = $20.00 − $16.40 = $3.60
Answer $3.60
95 marksCore

Oct/Nov 2025 · Paper 1 · 0580/13/O/N/25 · Q11

(a) Sam buys 3 apples at 40 cents each. He also buys 5 peaches. The total cost is $3.45. Find the cost of 1 peach.

(b) Pears cost 55 cents each. Bananas cost 36 cents each. Write an expression, in cents, for the cost of x pears and y bananas.

Show solution
Part (a)
  1. Work in cents so there are no decimals: $3.45 = 345 cents.
  2. Cost of the apples = 3 × 40 = 120 cents.
  3. Cost of the 5 peaches = 345 − 120 = 225 cents.
  4. One peach = 225 ÷ 5 = 45 cents
Answer 45 cents
Part (b)
  1. x pears cost 55 × x cents and y bananas cost 36 × y cents.
  2. Total cost = 55x + 36y
Answer 55x + 36y
103 marksCore

Oct/Nov 2025 · Paper 3 · 0580/31/O/N/25 · Q2

Complete this shopping bill: 3.4 kg of flour at $4.60 per kg = $…; 2.75 kg of sugar at $… per kg = $9.90; total = $…

Show solution
  1. Flour: cost = number of kg × price per kg = 3.4 × 4.60 = $15.64
  2. Sugar: price per kg = cost ÷ number of kg = 9.90 ÷ 2.75 = $3.60
  3. Total = 15.64 + 9.90 = $25.54
Answer $15.64 $3.60 $25.54
115 marksCore

Oct/Nov 2025 · Paper 3 · 0580/32/O/N/25 · Q14

(a) Ada works from Monday to Friday. Her working hours each day are 08 00 to 12 30 and 13 30 to 17 00. Find the number of hours she works in 5 days.

(b) Ada is paid $15.20 per hour. Work out her pay for these 5 days.

(c) On Saturday she is paid 11⁄2 times her normal hourly rate. Work out her hourly rate of pay for Saturday.

(d) Ada changes 370 euros into dollars. The exchange rate is $1 = 0.925 euros. Work out the amount she receives.

Show solution
Part (a)
  1. Morning: 08 00 to 12 30 is 4 hours 30 minutes = 4.5 hours.
  2. Afternoon: 13 30 to 17 00 is 3 hours 30 minutes = 3.5 hours.
  3. Each day = 4.5 + 3.5 = 8 hours. In 5 days: 5 × 8 = 40 hours
Answer 40 hours
Part (b)
  1. Pay = hours × rate = 40 × 15.20 = $608
Answer $608
Part (c)
  1. 11⁄2 times = 1.5 times. 1.5 × 15.20 = $22.80
Answer $22.80
Part (d)
  1. Each dollar costs 0.925 euros, so divide the euros by 0.925.
  2. 370 ÷ 0.925 = $400
Answer $400
122 marksCore

May/June 2025 · Paper 1 · 0580/11/M/J/25 · Q2

A bag of sweets costs $0.34. Arun buys 10 bags of sweets. Work out how much change he receives from $5.

Show solution
  1. Cost of 10 bags = 10 × $0.34 = $3.40 (multiplying by 10 moves the digits one place left).
  2. Change = money given − cost = $5.00 − $3.40.
  3. Change = $1.60
Answer $1.60

0580 Money and Exchange Rates past paper questions: Extended (Papers 2 and 4)

132 marksExtended

May/June 2026 · Paper 4 · 0580/43/M/J/26 · Q4

The exchange rate is $1 = 0.93 euros.

(a) Kit changes $350 into euros. Calculate the amount, in euros, that Kit receives.

(b) Jo changes 150 euros into dollars. Calculate the amount, in dollars, that Jo receives.

Show solution
Part (a)
  1. Each dollar is worth 0.93 euros, so to change dollars into euros, multiply by 0.93.
  2. 350 × 0.93 = 325.50 euros
Answer 325.50 euros
Part (b)
  1. To change euros into dollars, divide by 0.93.
  2. 150 ÷ 0.93 = 161.290…
  3. Round to the nearest cent: $161.29
Answer $161.29
142 marksExtended

Feb/Mar 2026 · Paper 4 · 0580/42/F/M/26 · Q4

The exchange rate between pounds (£) and dollars ($) is £1 = $1.28. The exchange rate between pounds and rupees is £1 = 115 rupees. A computer costs $576. Calculate the cost of the computer in rupees.

Show solution
  1. The two rates both use pounds, so change dollars into pounds first.
  2. $576 ÷ 1.28 = £450.
  3. Now change pounds into rupees: 450 × 115 = 51 750 rupees
Answer 51 750 rupees
152 marksExtended

Oct/Nov 2025 · Paper 4 · 0580/42/O/N/25 · Q5

One website sells a phone for 953 Yuan. A different website sells the same phone for $141. The exchange rate is 1 Yuan = $0.152. Calculate the difference between these phone prices. Give your answer in dollars, correct to the nearest cent.

Show solution
  1. Change the Yuan price into dollars: 953 × 0.152 = $144.856.
  2. Difference = 144.856 − 141 = 3.856.
  3. Round to the nearest cent (2 decimal places): $3.86
Answer $3.86

Question papers used on this page

All money and exchange rates questions above, listed by 0580 question paper code.

QP codeFile namePaperQuestions
0580/31/M/J/260580_s26_qp_31May/June 2026 · Paper 3 (Core)Q1, Q3
0580/32/M/J/260580_s26_qp_32May/June 2026 · Paper 3 (Core)Q3, Q9
0580/33/M/J/260580_s26_qp_33May/June 2026 · Paper 3 (Core)Q18
0580/43/M/J/260580_s26_qp_43May/June 2026 · Paper 4 (Extended)Q4
0580/32/F/M/260580_m26_qp_32Feb/Mar 2026 · Paper 3 (Core)Q4, Q15
0580/42/F/M/260580_m26_qp_42Feb/Mar 2026 · Paper 4 (Extended)Q4
0580/12/O/N/250580_w25_qp_12Oct/Nov 2025 · Paper 1 (Core)Q2
0580/13/O/N/250580_w25_qp_13Oct/Nov 2025 · Paper 1 (Core)Q11
0580/31/O/N/250580_w25_qp_31Oct/Nov 2025 · Paper 3 (Core)Q2
0580/32/O/N/250580_w25_qp_32Oct/Nov 2025 · Paper 3 (Core)Q14
0580/42/O/N/250580_w25_qp_42Oct/Nov 2025 · Paper 4 (Extended)Q5
0580/11/M/J/250580_s25_qp_11May/June 2025 · Paper 1 (Core)Q2

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