GCSE Maths · Edexcel 1MA1 · Grade Ladder · Geometry

Grade Ladder: Geometry and Measures

18 questions climbing from grade 1 to grade 9 across the geometry content of the Edexcel GCSE, two at each grade. Each question shows its grade, its specification code and whether it is non-calculator.

How to use this ladderFoundation students: work through Grades 1–5. Higher students: start at Grade 4 and push on to 9. Questions marked Non-calculator should be done without a calculator, as in Paper 1.
Grades 1–3 · Foundation
  1. (1 mark)
    Grade 1G3Non-calculator
    Two angles lie on a straight line. One is 65°. Find the other.
  2. (1 mark)
    Grade 1G17Non-calculator
    Find the perimeter of a rectangle 7 cm by 4 cm.
  3. (1 mark)
    Grade 2G16Non-calculator
    Find the area of a triangle with base 10 cm and height 6 cm.
  4. (1 mark)
    Grade 2G3Non-calculator
    Two angles of a triangle are 50° and 70°. Find the third.
  5. (1 mark)
    Grade 3G16Non-calculator
    Find the volume of a cuboid 5 cm by 4 cm by 3 cm.
  6. (2 marks)
    Grade 3G3Non-calculator
    Find the size of each interior angle of a regular hexagon.
Grades 4–5 · Foundation and Higher
  1. (2 marks)
    Grade 4G17
    Find the area of a circle of radius 6 cm, to 1 decimal place.
  2. (2 marks)
    Grade 4G20
    A right-angled triangle has shorter sides 5 cm and 12 cm. Find the hypotenuse.
  3. (2 marks)
    Grade 5G20
    A right-angled triangle has hypotenuse 10 cm and an angle of 35°. Find the side opposite the 35° angle, to 3 s.f.
  4. (2 marks)
    Grade 5G18
    Find the arc length of a sector with radius 8 cm and angle 45°. Give your answer to 3 s.f.
Grades 6–7 · Higher
  1. (2 marks)
    Grade 6G17
    A cone has radius 3 cm and height 7 cm. Find its volume, to 3 s.f. (V = ⅓πr²h)
  2. (2 marks)
    Grade 6G19Non-calculator
    Two similar shapes have lengths in the ratio 1 : 3. The smaller has area 8 cm². Find the area of the larger.
  3. (3 marks)
    Grade 7G22
    In triangle ABC, a = 8 cm, angle A = 40° and angle B = 65°. Find b, to 3 s.f.
  4. (2 marks)
    Grade 7G21Non-calculator
    Without a calculator, find the exact value of sin 30° + cos 60°.
Grades 8–9 · Higher
  1. (3 marks)
    Grade 8G22
    Two sides of a triangle are 7 cm and 9 cm, with an angle of 50° between them. Find the third side, to 3 s.f.
  2. (2 marks)
    Grade 8G23Non-calculator
    Find the area of a triangle with sides 6 cm and 9 cm and an included angle of 30°.
  3. (3 marks)
    Grade 9G25Non-calculator
    OA = a and OB = b. M is the midpoint of AB. Find OM in terms of a and b.
  4. (4 marks)
    Grade 9G19
    Two similar solids have surface areas 50 cm² and 72 cm². The smaller has volume 250 cm³. Find the volume of the larger.

Worked solutions

Show worked solutions
GCSE Maths · Edexcel 1MA1 · Grade Ladder · Geometry

Grade Ladder: Geometry and Measures — Worked Solutions

Full worked solutions to all 18 questions (36 marks).

Grades 1–3 · Foundation
  1. (1 mark)
    Grade 1G3Non-calculator
    Two angles lie on a straight line. One is 65°. Find the other.
    Solution
    1. Angles on a straight line add to 180°.
    115°
  2. (1 mark)
    Grade 1G17Non-calculator
    Find the perimeter of a rectangle 7 cm by 4 cm.
    Solution
    1. 7 + 4 + 7 + 4.
    22 cm
  3. (1 mark)
    Grade 2G16Non-calculator
    Find the area of a triangle with base 10 cm and height 6 cm.
    Solution
    1. ½ × 10 × 6.
    30 cm²
  4. (1 mark)
    Grade 2G3Non-calculator
    Two angles of a triangle are 50° and 70°. Find the third.
    Solution
    1. 180 − 50 − 70.
    60°
  5. (1 mark)
    Grade 3G16Non-calculator
    Find the volume of a cuboid 5 cm by 4 cm by 3 cm.
    Solution
    1. 5 × 4 × 3.
    60 cm³
  6. (2 marks)
    Grade 3G3Non-calculator
    Find the size of each interior angle of a regular hexagon.
    Solution
    1. Exterior angle = 360 ÷ 6 = 60°.
    2. Interior = 180 − 60.
    120°
Grades 4–5 · Foundation and Higher
  1. (2 marks)
    Grade 4G17
    Find the area of a circle of radius 6 cm, to 1 decimal place.
    Solution
    1. π × 6² = 36π.
    113.1 cm²
  2. (2 marks)
    Grade 4G20
    A right-angled triangle has shorter sides 5 cm and 12 cm. Find the hypotenuse.
    Solution
    1. √(5² + 12²) = √169.
    13 cm
  3. (2 marks)
    Grade 5G20
    A right-angled triangle has hypotenuse 10 cm and an angle of 35°. Find the side opposite the 35° angle, to 3 s.f.
    Solution
    1. opp = hyp × sin 35°.
    5.74 cm
  4. (2 marks)
    Grade 5G18
    Find the arc length of a sector with radius 8 cm and angle 45°. Give your answer to 3 s.f.
    Solution
    1. 45360 × 2π × 8 = 2π.
    6.28 cm
Grades 6–7 · Higher
  1. (2 marks)
    Grade 6G17
    A cone has radius 3 cm and height 7 cm. Find its volume, to 3 s.f. (V = ⅓πr²h)
    Solution
    1. ⅓ × π × 9 × 7 = 21π.
    66.0 cm³
  2. (2 marks)
    Grade 6G19Non-calculator
    Two similar shapes have lengths in the ratio 1 : 3. The smaller has area 8 cm². Find the area of the larger.
    Solution
    1. Area scale factor = 3² = 9.
    2. 8 × 9.
    72 cm²
  3. (3 marks)
    Grade 7G22
    In triangle ABC, a = 8 cm, angle A = 40° and angle B = 65°. Find b, to 3 s.f.
    Solution
    1. Sine rule: b/sin 65° = 8/sin 40°.
    2. b = 8 sin 65° ÷ sin 40° = 11.2797…
    11.3 cm
  4. (2 marks)
    Grade 7G21Non-calculator
    Without a calculator, find the exact value of sin 30° + cos 60°.
    Solution
    1. sin 30° = ½ and cos 60° = ½.
    1
Grades 8–9 · Higher
  1. (3 marks)
    Grade 8G22
    Two sides of a triangle are 7 cm and 9 cm, with an angle of 50° between them. Find the third side, to 3 s.f.
    Solution
    1. Cosine rule: c² = 7² + 9² − 2 × 7 × 9 × cos 50°.
    2. c² = 49.0088…
    7 cm
  2. (2 marks)
    Grade 8G23Non-calculator
    Find the area of a triangle with sides 6 cm and 9 cm and an included angle of 30°.
    Solution
    1. ½ × 6 × 9 × sin 30° = 27 × ½.
    13.5 cm²
  3. (3 marks)
    Grade 9G25Non-calculator
    OA = a and OB = b. M is the midpoint of AB. Find OM in terms of a and b.
    Solution
    1. AB = b − a.
    2. OM = OA + ½AB = a + ½(b − a).
    ½(a + b)
  4. (4 marks)
    Grade 9G19
    Two similar solids have surface areas 50 cm² and 72 cm². The smaller has volume 250 cm³. Find the volume of the larger.
    Solution
    1. Area ratio 50 : 72 = 25 : 36, so length ratio 5 : 6.
    2. Volume ratio 125 : 216.
    3. 250 × 216125.
    432 cm³

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